Probability Game Ideas Part 1

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ROCK PAPER SCISSORS.. BET!

INSTRUCTIONS / MECHANIC OF THE GAME:

              The game is called “ROCK PAPER SCISSORS:BET!” which is a mix of the traditional games of Rock, Paper, Scissors & Monopoly and has a total of five rounds to be played.  Instead of having a player count of 2-8 players like Monopoly, we will be following the amount of players Rock, Paper, Scissors has which is 2.

They will not use their hands to play, rather, there is a box in front of them. Inside of this box are various cards for the players to use. These are cards of 10 rocks, 9 papers, 8 scissors with also 3 bombs which is equal to 30 cards when added. The bombs are, when drawn, grants the opposing player easy money.

 As for the Monopoly part of the game, betting is involved. At the start of each round, the two players will have play money which totals up to $1300. The individual play money is  (1) $500, (2) $250, (2) $100, and (2) $50. It is also to be noted that at the start of each round, the players must bet 100$ at the start to exclude the possibility of players betting nothing. Players will then draw three cards from the box and through these three cards, you will bet the amount of money you want based on your confidence in the probability that you win that round. Players are also free to bluff.

To know who draws 3 cards first, the players will roll a dice. The player with the highest number will get 3 cards from the box first. Then, the second player will draw afterwards. The amount of cards also reset at the start of every round.

 When you win, you get the money you betted and the money betted by the opposing player, while the loser gets nothing. Each round ends when there is a player who won or if the three cards round up to a draw, thus another round begins. The game ends when one of the players has no more money left to bet which lets the other player automatically win overall.

This game will have no pointing system. Instead, this game’s winning condition involves which player accumulates a higher amount of money than the other player after the fifth round ends.  The game may also end when one of the players successfully gets all of the money from the other player before the fifth round begins.

 LUCKY SPACES

Instructions/Mechanics of the Game:

1. In a large space, such as a classroom, mark 8 spaces on every side of the classroom.

● If such a large space is not available, this game can be played like a board game using an illustration board with pieces resembling the players.

2. There must be at least 30 players in order to play with 8 marked spaces

3. The game has a player space where all players must reside before the start of the 1st round. Once the 1st round starts, nobody should be in the player space except for the eliminated.

4. The game master will give the players 10 seconds to choose a space that they believe is safe.

5. Each space has a maximum number of players depending on the round. The maximum number of players will depend on how many total players there are. Reason for this is to prevent an immediate drop in player count.

6. The game will use a draw lots system as well as a spin the wheel system. The draw lots are for choosing the winning plot and the losing plot while the spin the wheel will determine the fate of the losing plot.

7. The winning plot will answer a question to gain points. The losing plot will receive an event and all of the players except for one will be eliminated. The other plots will remain in the game with nothing.

8. For the rules of the pointing system, the players in the winning plot will be able to earn points depending on how fast and close their answer is to the solution and answer of each question.

● If by any chance, ALL players get the same answer, nobody earns points.

● If multiple but not all players get the same answer, the amount of points will rely on the sequence of players submitting their answers.

● If nobody got the question right, the losing and winning plots will switch places. The losers will get a chance to earn points while the winners will end up getting the fate of the losers.

9. The losing plot gets a random event from the spin the wheel system. They are to perform each event, the best player will win immunity and remain in the game while the others get eliminated.

10. If the event answer from the winning plot’s question comes true, the winning plot’s best player during that round will receive 10 points for each player in the winning plot with them.

11. Since each round, players get eliminated, the spaces get reduced by 1 space each time until the players reach Round 8 with one space remaining.

12. The last round will have one space, all players remaining in this space will answer the last question. However this last question will not determine the winner because the number of points will.

13. The player with the most points becomes the champion of “Lucky Spaces”.

Pointing System:

Round 1: 100-150 points

Round 2: 150-175 points

Round 3: 175-200 points

Round 4: 200-250 points

Round 5: 250-315 points

Round 6: 315-375 points

Round 7: 375-400 points

Round 8: 400-500 points

Bonus Points per Round: 10 points for each player in the winning plot with you (Example: Winning Plot has 6 players in it. Event happens and so the most accurate and fastest player will gain 50 points.)

●      All the more reason for all players to choose sides with less people and to aim for the best answer.

FINISH ME!

Instructions/Mechanics of the game:

1. Each player rolls the die once, and the player with the highest number gets to start the game.

2. Players take turns rolling the die and moving their game piece along the board. The number rolled on the die determines how many squares the player advances. For example, if you roll a 3, move your game piece three squares forward.

3. Some squares on the board may have special squares:

 Yellow Square: If your game piece lands on a yellow square, move 2 squares back.

 Red Square: If your game piece lands on a red square, you must pick a card with a question. Answer correctly to stay on your current square; if not correct, move back one square.

 Green Square: If your game piece lands on a green square, there is no consequence.

4. The first player to reach or exceed the final square wins the game.

PROBLEM OF THE GAME.

Question 1: What is the probability of neither a spade nor a jack card?

SOLUTION: Total number of outcomes = 52

The number of favorable outcomes = 36

13 spade + 4 jack – 1 jack of spade = 16

52 – 16 = 36 neither spade nor jack

P(E) = n(E) / n(S)

P(Neither Spade nor Jack) = 36/52 = 9/13

Question 2: A single die is rolled. Find the probability of rolling 2 or an odd number.

SOLUTION: Total number of outcomes = 6

The number of favorable outcomes = 4 (as there are 1 getting a 2 and 3 odd number)

P(E) = n(E) / n(S)

P(Odd number) = 4/6 = 2/3

Question 3: If I draw a card from a well-shuffled deck. Help me find the probability of the red cards.

SOLUTION: Total number of outcomes = 52

The number of favorable outcomes = 26 (13 hearts + 13 diamonds)

P(E) = n(E) / n(S)

P(Red) = 26/52 = 1/2

Question 4: If you flip a coin once, what is the probability of getting a head?

SOLUTION: Total number of outcomes = 2

The number of favorable outcomes = 1

P(E) = n(E) / n(S)

P(Head) = 1/2

Question 5: Given a standard die, find the probability of getting a 7.

SOLUTION: Total number of outcomes = 6

The number of favorable outcomes = 0

P(E) = n(E) / n(S)

P(a 7) = 0/6 = 0

Question 6: Each of the letters HELLO is written on a card. A card is chosen at random from the bag. What is the probability of getting the letter ‘L’?

SOLUTION: Total number of outcomes = 5

The number of favorable outcomes = 2 (as there are 2 letter ‘L’ in HELLO)

P(E) = n(E) / n(S)

P(L) = 2/5

Question 7: What is the probability of getting a sum of 7 when two dice are thrown?

SOLUTION: Total number of outcomes = 6 x 6 = 36

The number of favorable outcomes = 6 (1,6), (6,1), (2,5), (5,2), (3,4), (4,3)

P(E) = n(E) / n(S)

P(Sum of 7) = 6/36 = 1/6

Question 8: Find the probability of getting a numbered card when a card is drawn from the pack of 52 cards.

SOLUTION: Total number of outcomes = 52

The number of favorable outcomes = 36

Numbered card (2, 3, 4, 5, 6, 7, 8, 9, 10) 9 x 4 = 36

P(E) = n(E) / n(S)

P(Numbered card) = 36/52 = 9/13

Question 9: A whole number between 1 and 20 included is picked at random. What is the probability that the number picked is a prime number?

SOLUTION: Total number of outcomes = 20

The number of favorable outcomes = 8 (prime numbers are 2, 3, 5, 7, 11, 13,

17 and 19)

P(E) = n(E) / n(S)

P(Prime number) = 8/20 = 2/5

Question 10: A number is chosen at random from 1 to 10. What is the probability of selecting a multiple of 3?

SOLUTION: Total number of outcomes = 10

The number of favorable outcomes = 3 (multiple of 3 includes 3, 6, and 9)

P(E) = n(E) / n(S)

P(Multiple of 3) = 3/10

Question 11: What is the probability of drawing an ace from a deck of cards?

SOLUTION: Total number of outcomes = 52

                The number of favorable outcomes = 4          

                P(E) = n(E) / n(S)

                P(Ace) = 4/52 = 1/13

Question 12: If I roll a fair six-sided die, what is the probability of rolling an even number?

SOLUTION: Total number of outcomes = 6

The number of favorable outcomes = 3 (even numbers are 2, 4, 6)

P(E) = n(E) / n(S)

                P(Even number) = 3/6 = 1/2

FLIP!

Instructions/Mechanics of the game: 

There will be a total of 12 Cards. 24 cards have questions and the other 24 has answers. The goal of the players is to pair the right answer card and the right question card. The player with the most points at the end of the game when all the cards are flipped wins. To make things a little bit more interesting each time a player flips a card and it doesn’t pair their score goes down by 1.

Probability Questions:

Question 1: In a bag, there are 10 red balls and 5 blue balls. If one ball is randomly drawn from the bag, what is the possibility of selecting a red ball?

SOLUTION:

n(e)=10 (number of red balls)

 𝑛 ( 𝑠 ) = 15 (total number of balls) 

𝑝 ( 𝑒 ) = ¹⁰⁄₁₅ = ⅔

Question 2: In a standard deck of 52 playing cards, what is the possibility of drawing a heart or a diamond from the deck?

SOLUTION:

n(e)=26 (number of hearts and diamonds) 

𝑛 ( 𝑠 ) = 52 n(s)=52 (total number of cards)

𝑝 ( 𝑒 ) =²⁶⁄₅₂ = ½

Question 3: In a box, there are 4 green marbles and 6 yellow marbles. If one marble is randomly selected from the box, what is the possibility of selecting a green marble?

SOLUTION:

n(e)=4 (number of green marbles) 

𝑛 ( 𝑠 ) = 10 n(s)=10 (total number of marbles) 

𝑝 ( 𝑒 ) = ⁴⁄₁₀ = ⅖

Question 4: In a jar, there are 8 white candies and 2 black candies. If one candy is randomly picked from the jar, what is the possibility of selecting a black candy?

SOLUTION: 

𝑛 ( 𝑒 ) = 2 (number of black candies)

 𝑛 ( 𝑠 ) = 10 

𝑝 ( 𝑒 ) = ²⁄₁₀ = ⅕

Question 5: In a basket, there are 3 apples and 7 oranges. If one fruit is randomly chosen from the basket, what is the possibility of selecting an orange?

SOLUTION:

n(e)=7 (number of oranges)

𝑛 ( 𝑠 ) = 10 n(s)=10 (total number of fruits) 

𝑝 ( 𝑒 ) = ⁷⁄₁₀

Question 6: In a bag, there are 30 red balls and 20 blue balls. If one ball is randomly drawn from the bag, what is the possibility of selecting a red ball?

SOLUTION: 

N ( e )=30  ( number of red balls )

 𝑛 ( 𝑠 ) = 50 ( total number of balls ) 

𝑝 ( 𝑒 ) = ³⁰⁄₅₀ = ⅗

ROLL OF CHANCES

Instructions/Mechanics of the game: 

The mechanics if the game is simple, it is just like regular Snakes and Ladders, however there is a twist. The game involves mathematical questions, specifically Probability questions. The game needs 2 or more players given small figurines, a die, the set of questions (The Chance Box), a timer (adjustable), a small whiteboard, and the board itself inside the packaging.

You will play regular Snakes and Ladders, taking turns rolling a die and moving one’s character, having a race to the finish box. When you land on a snake, you have to draw a paper from the Chance Box containing Probability questions, if you answer the question correctly under 2 minutes (suggested time), you get to be safe and not go down the snake, when you answer incorrectly or even if your answer is right but exceed 2 minutes in answering, you have to go down the snake. The same mechanism applies to the ladders, you will answer in 2 minutes, when you answer correctly, you get to move up, and not, you don’t get to move up the ladder. Take note that your answers should be in simplest form, if your answer is not in simplest form, you will stay at your position.

When you reach the Finish Box, you are required to draw 3 questions out of the Chance Box (with or without timer for the Finish Box is optional), when you answer all of them correctly, you win, if not (even with one incorrect answer), you need to move 10 steps back.

The whiteboard can be used in solving, and players can create their own questions by writing the problem in the whiteboard to be given to the player who will solve the problem.

Pointing System

1. The number that will show on the die when it rolls, determines the amount of times you move per box.

2. If the answer is correct determines whether the player goes down the snake or up the ladder.

3. For each question, there is a time limit of 2 minutes to answer. If these conditions are not met, the player will not be able to go up the ladder, or they will go down the snake.

4. Whoever reaches the finish box first determines the winner of the game.

Terminologies

1. Figurines - Small characters to differentiate each player.

2. Chance Box - A box that contains 20 Probability questions wherein a player has to draw one.

3. Finish Box - The last box at the top left (100th box) determining the winner.

SOLUTION SHEET (Some Questions inside the Chance Box)

Question 1: You rolled a die, what is the probability of getting a 3?
SOLUTION

n(3) = 1

n(S) = 6

P(3) = ⅙

Question 2: You rolled a die, what is the probability of getting an even number?
SOLUTION

n(even) = 3

n(S) = 6

P(even) = ³⁄₆ = ½

Question 3: You have 12 marbles inside a bag. The amount of red marbles is 7, the amount of blue marbles is 5. You picked marbles 6 times, with red being chosen 4 times. Calculate the probability of getting a red marble.
SOLUTION

n(red) = 4

n(S) = 12

P(red) = ⁴⁄₆ = ⅔

Question 4: Calculate the probability of drawing a red card in a 52 standard deck of cards.
SOLUTION

n(red) = 26

n(S) = 52

P(red) = ²⁶⁄₅₂ = ½

Question 5: The probability of getting numbers 4 and above in a die
SOLUTION

n(4 and above) = 3

n(S) = 6

P(4 and above)= ³⁄₆ = ½

Question 6: You are playing a game of darts, there are 10 balloons, there are 5 pink balloons and 5 green balloons. You threw darts 3 times, hit 2 green balloons and one pink balloon. Calculate the probability of hitting a green balloon.
SOLUTION

n(green balloon) = 2

n(S) = 3

P(green balloon)= ⅔

Question 7: In the closet there are 4 red shirts, 3 green shirts, 5 blue shirts. After three days there were only nine shirts left, if he wore 2 blue shirts and 1 red shirt during the three days. What is the probability of him choosing a blue shirt?

SOLUTION

n(blue shirt) = 3

n(S) =  9

P(blue shirt) = ³⁄₉ = ⅓

  

Question 8: In a jar, there are 11 yellow marbles, 9 purple marbles, 12 orange marbles. After picking 8 marbles out, there are 5 purple marbles, and 11 orange marbles left. What is the probability of picking a yellow marble?

SOLUTION

n(yellow marble) = 8

n(S) = 24

P(yellow marble) = ⁸⁄₂₄ = ⅓

Question 9: In a wheel of names, there are 14 boys and 16 girls. After spinning the wheel 17 times there are only 6 boys left. What is the probability of a girl on the next spin?

SOLUTION

n(girl) = 7

n(S) = 13

P(girl) = ⁷⁄₁₃

Question 10:John played 20 games of Valorant in a span of 10 hours.  He won 9 games and drew thrice. What is the probability of losing in the span of 10 hours?

SOLUTION

n(losing) = 8

n(S) = 20

P(losing) = ⁸⁄₂₀ = ⅖

Question 11: You are spinning a wheel. There are 3 red parts, 7 blue parts ad 5 yellow parts. What is your probability of not getting a blue?

SOLUTION

n(not blue) = 8

n(S) = 15

P(not blue) = ⁸⁄₁₅

Question 12: Reverie has a white, a black, and a gray shirt, a blue and a yellow skirt, and a black hat. What is the probability of her outfit containing the color yellow?

SOLUTION

n(yellow) = 2

n(S) = 6

P(yellow) = ²⁄₆ = ⅓

Question 13: Rafael challenged his friend to a game of badminton. Out of the 13 rounds they played, Rafael won 6, his friend won 5 and they had 2 draws. What is the probability of getting a draw?

SOLUTION

n(draw) = 2

n(S) = 13

P(draw) = ²⁄₁₃

Question 14: Reverie drew 15 cards from a deck of 52 cards. She got 12 black cards and 3 red cards. What is the probability of getting a red card?

SOLUTION

n(red) = 3

n(S) = 15

P(red) = ³⁄₁₅ = ⅕

Question 15: Gaby and Mary played 26 games of rock paper scissors. Gaby won 12, Mary won 8, and they had 6 draws. What is the probability of Gaby winning?

SOLUTION

n(w) = 12

n(S) = 26

P(w) = ¹²⁄₂₆ = ⁶⁄₁₃

Question 16: You are rolling a pair of dice. What is the probability of the two dice to show the same number?

SOLUTION

n(same) = 6

n(S) = 36

P(same) = ⁶⁄₃₆ = ⅙

Question 17: Mary plans on adopting a cat. There are 3 black cats, 5 ginger cats, and 2 calico cats at the pet store. What is the probability of Mary not getting a black cat?

SOLUTION

n(not black) = 7

n(S) = 10

P(not black) = ⁷⁄₁₀

Question 18: A box contains 3 black balls, 6 red balls, 7 white balls, and 2 blue ball. What is the probability of getting a red or  blue ball?

SOLUTION

n(red or blue) = 8

n(S) = 18

P(red or blue) = ⁸⁄₁₈ = ⁴⁄₉

Question 19: What is the probability of getting an ace or king in a deck of cards?

SOLUTION

n(ace or king) = 8

n(S) = 52

P(ace or king) = ⁸⁄₅₂ = ²⁄₁₃

Question 20: You flipped a coin 5 times. You got 3 heads and 2 tails. What is the probability of getting a head?

SOLUTION

n(heads) = 3

n(S) = 5

P(heads) = ⅗

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