MATH LESSON
FACTORING: DIFFERENCE OF TWO SQUARES
When you see two perfect squares separated by a minus sign, you can factor them into a sum and difference!
A difference of two squares is a binomial of the form a² − b², which always factors into (a + b)(a − b).
a² − b² = (a + b)(a − b)
a² − b²
=
(a + b)
×
(a − b)
How to Recognize It
A Difference of Two Squares (DOTS) must meet ALL three conditions:
1. It must be a binomial (exactly 2 terms)
2. Both terms must be perfect squares
3. The sign between them must be MINUS (−)
a² + b² is NOT a difference of two squares!
a² − b² YES, this is DOTS!
How to Identify a and b
For each perfect square term, find its square root. That gives you a and b:
Given: x² − 25
First term: x² = (x)² → a = x
Second term: 25 = (5)² → b = 5
Substitute into the pattern:
(a + b)(a − b) = (x + 5)(x − 5)
Order Does NOT Matter!
Even if the smaller square comes first, it is still DOTS. Just be careful with signs:
x² − 25 = (x + 5)(x − 5)
25 − x² = (5 + x)(5 − x)
Both are correct! The larger term determines which is a and which is b.
Common Mistakes!
Mistake 1: Factoring a sum of squares (a² + b²).
x² + 25 = (x + 5)(x + 5) × WRONG
x² + 25 = PRIME (cannot be factored using DOTS) ✓
Mistake 2: Using the same sign in both factors.
x² − 25 = (x + 5)(x + 5) × WRONG
x² − 25 = (x + 5)(x − 5) ✓ One PLUS, one MINUS!
Mistake 3: Forgetting to take the square root of coefficients.
4x² − 9 = (4x + 9)(4x − 9) × WRONG
4x² − 9 = (2x + 3)(2x − 3) ✓ √4 = 2, √9 = 3
Worked Examples
Example 1: Factor: x² − 36
a² = x² → a = x | b² = 36 → b = 6
→ (x + 6)(x − 6)
a² = x² → a = x | b² = 36 → b = 6
→ (x + 6)(x − 6)
Example 2: Factor: 4x² − 25
a² = 4x² = (2x)² → a = 2x | b² = 25 → b = 5
→ (2x + 5)(2x − 5)
a² = 4x² = (2x)² → a = 2x | b² = 25 → b = 5
→ (2x + 5)(2x − 5)
Example 3: Factor: 9x² − 16
a² = 9x² = (3x)² → a = 3x | b² = 16 → b = 4
→ (3x + 4)(3x − 4)
a² = 9x² = (3x)² → a = 3x | b² = 16 → b = 4
→ (3x + 4)(3x − 4)
Example 4: Factor: 25x² − 1
a² = 25x² = (5x)² → a = 5x | b² = 1 = (1)² → b = 1
→ (5x + 1)(5x − 1)
a² = 25x² = (5x)² → a = 5x | b² = 1 = (1)² → b = 1
→ (5x + 1)(5x − 1)
Example 5: Factor: x&sup4; − 81
a² = x⁴ = (x²)² → a = x² | b² = 81 → b = 9
→ (x² + 9)(x² − 9) (x²−9 can be factored further!)
a² = x⁴ = (x²)² → a = x² | b² = 81 → b = 9
→ (x² + 9)(x² − 9) (x²−9 can be factored further!)
Shortcut: Find the square root of each term, then write (root + root)(root − root). Always one PLUS and one MINUS!
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MATH QUIZ
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